Menu build in python with KeyboardInterrupt exception

import sys

import os

import requests

def print_menu():

    print 30 * "-", "MENU", 30 * "-"

    print "1. Call Date"

    print "2. Check logged users"

    print "3. GET Request"

    print "4. Exit"

    print 67 * "-"

loop = True

try:

      while loop:

            print_menu()

            choice = input("enter your choice [1-4]: ")

            if choice == 1:

                  x = os.system('date')

                  print x

            elif choice == 2:

                  print "logged uers"

                  os.system('who')

            elif choice == 3:

                  address = 'https://google.com'

                  print "GET Request of {}".format(address)

                  req = requests.get(address)

                  print(req.encoding)

                  print(req.status_code)

            else:

                  print "exit"

                  sys.exit()

except KeyboardInterrupt: